Y=2x^2-2x+4=0

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Solution for Y=2x^2-2x+4=0 equation: 



=2Y^2-2Y+4=0

We move all terms to the left:

-(2Y^2-2Y+4)=0

We get rid of parentheses

-2Y^2+2Y-4=0

a = -2; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·(-2)·(-4)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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